To achieve a 0.5% salinity target in brine using 1L of water, how much salt is required?

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To achieve a 0.5% salinity in brine using 1 liter of water, you need to understand that a percentage by weight means how many grams of solute (in this case, salt) are needed per 100 milliliters of solution. In this scenario, 0.5% salinity indicates that there should be 0.5 grams of salt in every 100 milliliters of water.

Since there are 1000 milliliters in 1 liter of water, you can calculate the amount of salt needed for the entire liter as follows:

  • Start by finding out how much salt is needed for 1 liter, which contains 10 times the amount of a 100 milliliter portion (because 1000 ml = 10 x 100 ml).

  • Therefore, if 0.5 grams is required for 100 ml, you multiply this by 10 to find out the salt required for 1 liter.

Doing the calculation:

0.5 grams x 10 = 5 grams of salt.

This calculation shows that to achieve a 0.5% salinity in 1 liter of water, you need exactly 5 grams of salt, confirming the accuracy of the answer

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